ITA 2006 — Questão 18

$\left(-\dfrac{91}{12};\, -\dfrac{81}{12}\right)$

$\left(-\dfrac{81}{12};\, -\dfrac{74}{12}\right)$

$\left(-\dfrac{74}{12};\, -\dfrac{30}{12}\right)$

$\left(\dfrac{30}{12};\, \dfrac{74}{12}\right)$

$\left(\dfrac{75}{12};\, \dfrac{91}{12}\right)$